Question

plz help.... can't get through this numerical!​

Answer 1

Answer:

1 answer --- 9 ohm

2 answer 2A

Answer 2

Answer:

$\boxed{\text{Part (i): 9 ohm}}\\\\\boxed{\text{Part (ii): 2 ampere}}$

Explanation:

$\text{R1 and R2 are connected in parallel}\\\\\\\boxed{\frac{1}{ER} = \frac{1}{R1} + \frac{1}{R2}}\\\\\\\frac{1}{ER} = \frac{1}{12} + \frac{1}{12}\\\\\frac{1}{ER} = \frac{1}{6}\\\\\boxed{\text{R = 6 ohm}}\\\\\text{Now, for Equivalent Resistance across the circuit, we must calculate}\\\text{ER + R3 as they are connected in series!}\\\\\\\boxed{\text{R = ER + R1}}\\\\\\\text{R = 6 + 3}\\\\\\\boxed{\text{Answer to part (i): R = 9 ohm}}\\\\\\\text{According to Ohm's Law:}$

$\\\\\boxed{\text{V = IR}}\\\\\\\text{Circuit is connected to 15V supply. Hence, V = 15V}\\\\\text{Therefore, 18 = 9I}\\\\\\\boxed{\text{Answer to part (ii): I = 2A}}$

Hope this helps! If it does, feel free to mark it brainliest! Thanks :D