plz help class 10 th trigonometry in 3 Rd ques there is sec into cosec + cot
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sin@/(1-cos@) + tan@/(1+cos@),
[sin@.(1+cos@) + tan@.(1-cos@)]/(1-cos²@),
[sin@[email protected]@+tan@[email protected]@]/sin²@,
[sin@[email protected]@+sin@/cos@ - sin@/cos@ .cos@]/sin²@,
[sin@[email protected]@+sin@/cos@ - sin@]/sin²@,
then
[1+cos@+1/cos@ - 1]/sin@,
[cos@+1/cos@]/sin@,
(cos@+sec@)/sin@,
then it will becomes
cos@/sin@ + sec@/sin@,
cot@ [email protected]@,
hence
L.H.S=R.H.S
[sin@.(1+cos@) + tan@.(1-cos@)]/(1-cos²@),
[sin@[email protected]@+tan@[email protected]@]/sin²@,
[sin@[email protected]@+sin@/cos@ - sin@/cos@ .cos@]/sin²@,
[sin@[email protected]@+sin@/cos@ - sin@]/sin²@,
then
[1+cos@+1/cos@ - 1]/sin@,
[cos@+1/cos@]/sin@,
(cos@+sec@)/sin@,
then it will becomes
cos@/sin@ + sec@/sin@,
cot@ [email protected]@,
hence
L.H.S=R.H.S
Anonymous:
yess sure
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