Question

plz help..................?!?!?!!!??

find volume of cylinder?!
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Answer 1

$\huge{\underline{\underline{\sf{\purple{Required\:Solution:}}}}}$

Volume of cylinder B is greater.

For Cylinder A :-

$\displaystyle{\sf{\:\:\:\:\:\:\:\:r(radius)\:=\: \dfrac{7}{2}cm}}$

$\displaystyle{\sf{\:\:\:\:\:\:\:\:h(height)\:=\: 14cm}}$

$\displaystyle{\boxed{\sf{ Volume\:=\: \pi r^{2}h}}}$

Substitute the values and simplify it

$\displaystyle{\sf{\:\:\:\:\:\:\:\:\:\:= \dfrac{22}{7} \times \bigg(\frac{7}{2}^{2} \bigg)\times14}}$

$\large{\boxed{\sf{\orange{= 539 cm^{3}}}}}$

For Cylinder B:-

$\displaystyle{\sf{\:\:\:\:\:\:\:\:r(radius)\:=\: \dfrac{14}{2}cm=7cm}}$

$\displaystyle{\sf{\:\:\:\:\:\:\:\:h(height)\:=\: 7cm}}$

$\displaystyle{\boxed{\sf{ Volume\:=\: \pi r^{2}h}}}$

Substitute the values and simplify it.

$\displaystyle{\sf{\:\:\:\:\:\:\:\:\:\:= \dfrac{22}{7} \times (7^{2})\times7}}$

$\large{\boxed{\sf{\orange{= 1078 cm^{3}}}}}$

By actual calculation of volumes of both the cylinders, it is verified that the volumes of cylinder B is greater.

For Cylinder A

$\displaystyle{\boxed{\sf{ \:\:\:Surface\:area\:=\:2 \pi r(r+h)}}}$

Substitute the values and simplify it

$\displaystyle{\sf{\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 2 \times \dfrac{22}{7} \times \dfrac{7}{2} \times \bigg( \dfrac{7}{2} + 14\bigg)}}$

$\displaystyle{\sf{\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 2 \times \dfrac{22}{7} \times \dfrac{7}{2} \times \dfrac{35}{2}}}$

$\large{\boxed{\sf{\pink{=\:385\:cm^{2}}}}}$.

For Cylinder B

$\displaystyle{\boxed{\sf{ \:\:\:Surface\:area\:=\:2 \pi r(r+h)}}}$

Substitute the values and simplify it.

$\displaystyle{\sf{\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 2 \times \dfrac{22}{7} \times 7\times (7+7)}}$

$\displaystyle{\sf{\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 2 \times \dfrac{22}{7} \times 7 \times 14}}$

$\large{\boxed{\sf{\pink{=\:616\:cm^{2}}}}}$.

By actual calculation of surface area of both the cylinders, we observed that the cylinder with greater volume has greater surface area.

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Answer 2

Answer:

solution

Volume of cylinder B is greater.

For Cylinder A :-

$\displaystyle{\sf{\:\:\:\:\:\:\:\:r(radius)\:=\: \dfrac{7}{2}cm}}$

$\displaystyle{\sf{\:\:\:\:\:\:\:\:h(height)\:=\: 14cm}}$

$\displaystyle{\boxed{\sf{ Volume\:=\: \pi r^{2}h}}}$

Substitute the values and simplify it

$\displaystyle{\sf{\:\:\:\:\:\:\:\:\:\:= \dfrac{22}{7} \times \bigg(\frac{7}{2}^{2} \bigg)\times14}}$

$\large{\boxed{\sf{\pink{= 539 cm^{3}}}}}$

For Cylinder B:-

$\displaystyle{\sf{\:\:\:\:\:\:\:\:r(radius)\:=\: \dfrac{14}{2}cm=7cm}}$

$\displaystyle{\sf{\:\:\:\:\:\:\:\:h(height)\:=\: 7cm}}$

$\displaystyle{\boxed{\sf{ Volume\:=\: \pi r^{2}h}}}$

Substitute the values and simplify it.

$\displaystyle{\sf{\:\:\:\:\:\:\:\:\:\:= \dfrac{22}{7} \times (7^{2})\times7}}$

$\large{\boxed{\sf{\orange{= 1078 cm^{3}}}}}$

By actual calculation of volumes of both the cylinders, it is verified that the volumes of cylinder B is greater.

For Cylinder A

$\displaystyle{\boxed{\sf{ \:\:\:Surface\:area\:=\:2 \pi r(r+h)}}}$

Substitute the values and simplify it

$\displaystyle{\sf{\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 2 \times \dfrac{22}{7} \times \dfrac{7}{2} \times \bigg( \dfrac{7}{2} + 14\bigg)}}$

$\displaystyle{\sf{\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 2 \times \dfrac{22}{7} \times \dfrac{7}{2} \times \dfrac{35}{2}}}$

$\large{\boxed{\sf{\pink{=\:385\:cm^{2}}}}}$.

For Cylinder B

$\displaystyle{\boxed{\sf{ \:\:\:Surface\:area\:=\:2 \pi r(r+h)}}}$

Substitute the values and simplify it.

$\displaystyle{\sf{\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 2 \times \dfrac{22}{7} \times 7\times (7+7)}}$

$\displaystyle{\sf{\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 2 \times \dfrac{22}{7} \times 7 \times 14}}$

$\large{\boxed{\sf{\blue{=\:616\:cm^{2}}}}}$.

By actual calculation of surface area of both the cylinders, we observed that the cylinder with greater volume has greater surface area.

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