plz help for 10 points
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we can prove by proving the triangles abd and ADC congruent
angle abd =angle acd=90° ( angles in a semicircle are 90°)
AD=AD common side
AB=AC chords equidistant from the centre are equal.
therefore TRIANGLE ABD IS CONGRUENT WITH TRIQNGLE ACD. by SAS
therefore angles bad=angle dac corresponding parts of congruent triangles are equal. therefore AD bisects angles BAC.
Similarly AD bisects BDC
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