Question

plz help for this question​

Answer 1

Answer:

U can use Pythagoras theorem, find the hypotenis and solve, very simple, if u still have doubt I'll solve it then

Answer 2

Step-by-step explanation:

in first fig., Y=16 cm, (tangents from an external point are same in length.)

and X is hypotenuse so, (16)2 + (30)2=(x)2

256+900=1156=(34)2

so, X=34cm.

in second fig.,the triangle is right-angled.(angle in a semicircle by diameter is 90)

so, (5)2+(12)2=(x)2

25+144=169=(13)2

so, X=13cm.=diameter.

Y = r =d/2 =13/2 =6.5cm

in third fig., Y=24cm (tangents from an external point are same in length.)

as angle suspended by tangent with radius at the point of contact is 90,

(x)2=(18)2+(24)2

=324+ 576=900=(30)2

so, X=30cm.