Question

plz help frequency question​

Answer 1

Let the lower limit be x

∴upper limit =(x+8) (∵ class size is 8)

mid value of class =(upper limit +lowerlimt)÷2

⇒30 =[(x+8)+x]÷2

⇒60=2x+8

⇒60 - 8 =2x

⇒52 =2x

∴x =26