Question

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20th question

Answer 1

Answer:

x  = 58°

Step-by-step explanation:

in Δ AOB

∠OAB + ∠OBA + ∠AOB = 180°

OA = OB (Radius)

=> ∠OAB = ∠OBA = 32°

∠SAO = 90°  ( tangent)

∠SAO = x  + ∠OAB

=> 90° = x + 32°

=> x  = 58°

Additional info

=> 32° + 32° + ∠AOB = 180°

=> ∠AOB = 116°

∠ACB = (1/2) ∠AOB = 116/2  = 58°