plz help guys.. and plzz once aagain..
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9×(81)^x = (27)^(3-x). ∆ { 1/x = x ^(-1) }
prime factors
(3^2)× (3^4x) = 3^(9-3x). ∆{when base same power will add)}
3^(2+4x) = 3^(9-3x) ∆{both side base are equal so power should also equal }
2+4x = 9- 3x
7x = 7
x = 1
prime factors
(3^2)× (3^4x) = 3^(9-3x). ∆{when base same power will add)}
3^(2+4x) = 3^(9-3x) ∆{both side base are equal so power should also equal }
2+4x = 9- 3x
7x = 7
x = 1
adityakumar96:
thnk u bhai ...
welcome brother
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