Question

Plz help guys thankful to you ​

Answer 1

Answer:

$x+y+z=6 \\ x ^{2} + y ^{2} + z ^{2} +2(xy+yz+zx)=6 ^{2} \\ x {}^{2} +y ^{2} +z ^{2} +2(11)=36 \\ x {}^{2} + y {}^{2} + z {}^{2} =36−22 \\ x {}^{2} + y {}^{2} + z {}^{2} =14$

Answer 2

Answer:

x + y + z = 6

xy + yz + zx = 11

(x + y + z)² = x² + y² + z² + 2xy + 2yz + 2zx

(6)² = x² + y² + z² +2(xy + yz + zx)

36 = x² + y² + z² + 2(11)

36 - 22 = x² + y² + z²

x² + y² + z² = 14

hope it will help you dear