plz help how to find the answer of ques.4
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For the smaller sector,
radius, r = 3.5 cm
angle subtended at centre, θ = 40
For the larger sector,
radius, R = 7 cm
θ = 40
Area of shaded region = Area of larger sector - Area of smaller sector
= (π R² θ)/360 - (π r²θ) / 360
= πθ/360 (R² - r²)
= 22/7 * 40/360 (7² - 3.5²)
= 22/7 * 1/9 (49 - 12.25)
= 22/63 * 36.75
= 808.5/63
= 115.5/9
= 12.8333333333
≈ 12.83 cm²
radius, r = 3.5 cm
angle subtended at centre, θ = 40
For the larger sector,
radius, R = 7 cm
θ = 40
Area of shaded region = Area of larger sector - Area of smaller sector
= (π R² θ)/360 - (π r²θ) / 360
= πθ/360 (R² - r²)
= 22/7 * 40/360 (7² - 3.5²)
= 22/7 * 1/9 (49 - 12.25)
= 22/63 * 36.75
= 808.5/63
= 115.5/9
= 12.8333333333
≈ 12.83 cm²
Answered by
1
area of shaded region = area of large sector - area of small sector
area of shaded region = θ/360*πr₁² - Φ/360*πr₂²
=40/360*πr₁² - 40/360*πr₂²
=1/9*22/7[7²-3.5²]
=22/63*36.75
=12.83333
area of shaded region = θ/360*πr₁² - Φ/360*πr₂²
=40/360*πr₁² - 40/360*πr₂²
=1/9*22/7[7²-3.5²]
=22/63*36.75
=12.83333
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