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The resistors of 6 ohm and 3 ohm are connected in parallel. Therefore, their combined resistance can be calculated as
1/R=1/R1+1/R2
1/R=1/6+1/3
R= 2 ohms
(b) The p.d. across the combined resistance, V= IR
Here I = 6A and combined resistance = 2 ohms.
So, V= 6 x 2 = 12 V
(c) In parallel connection potential difference remains constant, so Potential difference across 3ohm resistor =12 V
(d) The current in the 3Ω resistor
I= V/R1
I= 12/3 =4A
(e) Current flowing through the 6 ohm resistor = V/R2 = 12/6 = 2 A
The resistors of 6 ohm and 3 ohm are connected in parallel. Therefore, their combined resistance can be calculated as
1/R=1/R1+1/R2
1/R=1/6+1/3
R= 2 ohms
(b) The p.d. across the combined resistance, V= IR
Here I = 6A and combined resistance = 2 ohms.
So, V= 6 x 2 = 12 V
(c) In parallel connection potential difference remains constant, so Potential difference across 3ohm resistor =12 V
(d) The current in the 3Ω resistor
I= V/R1
I= 12/3 =4A
(e) Current flowing through the 6 ohm resistor = V/R2 = 12/6 = 2 A
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