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3/5 of a pole is in the mud. When 1/3 of this part is pulled out ,5/4m of the pole is still in the mud.What is the full length of the pole??
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Let, the length of the pole be, 'x'
The portion of the pole in the mud is = (x*3/5)
= 3x/5
1/3 part of 3x/5 = (3x/5)*(1/3)
= x/5
After pulling up x/5 part of the pole, the portion of the pole remains in the mud = (3x/5)-(x/5)
= (3x-x)/5
= 2x/5
By condition,
2x/5 = 5/4
⇒ 2x = (5*5/4)
⇒ x = (5*5/4*2)
⇒ x = 25/8
⇒ x = 3.125 m
So, the full length of the pole is 3.125 m
(Ans): 3.125 m.
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Answer:
3.125 m is Tye correct answer
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