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PHYSICS CLASS12 PLZZZZZZZZZZ
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Answer:According to the Ampere's circuital law,magnetic field in a loop is 4π×10^-7×n×i where n is the no: of turns and i be the current. Here current in the loop is i/2. So the field inside the center of the loop is 2π×10^-7×n×i
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Magnetic field due to current through the semi−circular arc APB:
B1=μ04π2Ir (Perpendicular to the paper and inward)
Magnetic field due to current through the semi−circular arc AQB:
B2=μ04π2Ir (Perpendicular to the paper and outward)
As B1 and B2 are equal and opposite, the net magnetic field at the point C is equal to zero.
Read more on Brainly.in - https://brainly.in/question/12289139#readmore
B1=μ04π2Ir (Perpendicular to the paper and inward)
Magnetic field due to current through the semi−circular arc AQB:
B2=μ04π2Ir (Perpendicular to the paper and outward)
As B1 and B2 are equal and opposite, the net magnetic field at the point C is equal to zero.
Read more on Brainly.in - https://brainly.in/question/12289139#readmore
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