Question

plz help ...I promise to mark u brainliest!!​

Answer 1

Answer:

7/2 or 3.5

Step-by-step explanation:

Given 4^X1 = 5. Taking logarithms on both sides, log 4^X1 = log 5 %3D Or, X1 log 4 = log 5 (Using the formula log p^m =m log p) This yields X1 = log 5/log 4 Similarly, 5^X2 = 6 gives X2 log 6/log 5 6^X3 = 7 gives = log 7/log 6 %3D 126^X123 = 127 gives X123 = log 127/log 126 127^X124 = 128 gives X124 log 128/log 127 %3D Substituting the above values for X1, X2, X3, X123 and X124, we get Value of the product X1 X2 X3 .X123 X124127^X124 = 128 gives X124 = log 128/log 127 Substituting the above values for X1, X2, X3, .X123 and X124, we get Value of the product X1 X2 X3 X123 X124 = X1. X2. X3. X123. X124 = log 5/log 4. log 6/log 5. log 7/log 6 . log 127/log 126. log 128/log 127 We see that the numerators and the denominators of alternate ratios cancel out, and we are left with only the denominator of the first term and the numerator of the last term. Thus, Value of the product X1 X2 X3 X4. X123 X124 = (1/log 4). log 128 = log 128/log 4 = log 2^7 /log 2^2 = 7log 2/2log2 %3D %3D = 7/2 = 3.5