Question

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The length of a rectangle is 8 in. more than its width. The perimeter is 52 in. What is the length of the rectangle?

Answer 1

Let breadth of rectangle be = b, then length = b + 8

Perimeter of rectangle = 2 x (length+breadth)
                                = 2 x [ b + (b + 8)] = 2(2b + 8) = 52
                                                        Hence b = 9 in
                                                         Hence length = 9+8 = 17 in

Answer 2

PERIMETER OF A RECTANGLE=2  (length+breadth)
let x be breadth ,and x+8 be length
52=2(x(x+8)
52=2(2x+8)
52/2=2x+8
26=2x+8
26-8=2x
18=2x
x=9
length=9+7=17 in,breadth=9 in

2.3n+6=15
      3
 n+2=15
 n=15-2=13