Plz help i will mark you as brainlist . Determine the value of k for which the equation x square - 2(1+3k)x + 7(3+2k) = 0 has equal roots.
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Hey
Here is your answer,
X^2 - 2 (1+3k) x + 7 ( 3+2k ) = 0
X^2 - (2+6k)x + (21+14k)=0
b^2 - 4ac = 0
-(2+6k)^2 - 4 x 1 x ( 21+14k) = 0
- ( 4+36k ^2 + 24k ) - (84 + 56k) = 0
-4 - 36k^2 - 24k - 84 - 56k = 0
-36k ^2 - 80k - 88 = 0
÷ 2
-18k ^2 - 40k - 44 = 0
÷2
-9k ^2 - 20k - 22 =0
9k ^2 + 20k + 22 =0
solve this equation to get the value of k.
Hope it helps you!
Here is your answer,
X^2 - 2 (1+3k) x + 7 ( 3+2k ) = 0
X^2 - (2+6k)x + (21+14k)=0
b^2 - 4ac = 0
-(2+6k)^2 - 4 x 1 x ( 21+14k) = 0
- ( 4+36k ^2 + 24k ) - (84 + 56k) = 0
-4 - 36k^2 - 24k - 84 - 56k = 0
-36k ^2 - 80k - 88 = 0
÷ 2
-18k ^2 - 40k - 44 = 0
÷2
-9k ^2 - 20k - 22 =0
9k ^2 + 20k + 22 =0
solve this equation to get the value of k.
Hope it helps you!
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