Math, asked by Anonymous, 1 year ago


plz help........

If the nth term of a progression be a linear expression in n,then prove that this progression is an A.P.

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Answered by GovindRavi
20
hope this hlp.......
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Answered by Anonymous
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let \: the \: nth \: term \: of \: a \: given \: progression \: be \: given \: by \\ t _{n} = an + b \:  \: where \: a \: and \:  \: b \:  \: are \: constant \\ then \: t _{n - 1} = a(n - 1) + b = (an + b) - a \\  \therefore \: t _{n} - t _{n - 1} = (an + b) - (an + b)  + a = a \:  \\ which \: is \: constant \\ hence \: the \: given \: progression \: is \: an \: ap

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