Question

plz help in my assignment and plz solve it step by step​

Answer 1

Answer:

<RPS=40⁰ and <PQS=70⁰

Step-by-step explanation:

In ∆PSR

<PSR= 90⁰(Right Angle Triangle)

<PRS=50⁰

<RPS=?

Therefore, using angle sum property of a triangle

<PSR+<PRS+<RPS=180°

90⁰+50⁰+<RPS=180⁰

140⁰+<RPS=180⁰

<RPS=180⁰-140⁰

<RPS=40⁰

And Since <QPR=60⁰

Therefore <QPS= <QPR-<RPS

<QPS=60⁰-40⁰

<QPS=20⁰

Now,

In ∆QPS

<QSP=90⁰

<QPS=20⁰

<PQS=?

Therefore, using angle sum property of a triangle

<QSP+<QPS+<PQS=180⁰

90⁰+20⁰+<PQS=180⁰

110⁰+<PQS=180⁰

<PQS=180⁰-110⁰

<PQS=70⁰

ANS---Therefore <RPS=40⁰ and <PQS=70⁰