plz help it is seriously urgent please please please please please please please please
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The three angles of ΔCDE are the following:
- ∠C = 5x - 10°
- ∠D = 50°
- ∠E = 188° - 9x
By triangle angle sum
5x - 10 + 50 + 188 - 9x = 180
And
-4x + 40 + 8 = 0
Then
-4x = -48
Therefore
x = 12
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Therefore two remaining angles are
∠C = 60 - 10 = 50°
∠E = 188 - 108 = 80°
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