Question

*PLZ HELP IT'S DUE IN 2HRS*
So if a cart (m= 16 kg) is currently traveling with a velocity of 3 m/s The cart then gains speed, achieving a new velocity of 14 m/s after 22 seconds.

What would be the calculated net force the Net force experienced by the cart during the 22 second interval and why?
A.) + 8 N
B.) + 16 N
C.) + 32 N
D.) There was no applied force on the object

Answer 1

Given:-

→ Mass of the cart = 16kg

→ Initial velocity of the cart = 3m/s

→ Final velocity of the cart = 14m/s

→ Time taken = 22s

To find:-

→ Net force experienced by the cart

Solution:-

We know that if the velocity of a body is changing i.e. if it has acceleeation, then there also must be a force acting on the body. In this case, as the velocity of the cart is changing do there must be a force acting.

By Newton's 2nd law of motion, we know that:-

=> F = m(v - u)/t

Where:-

• F is the net force acting

• m is mass of the body

• v is final velocity of the body

• u is initial velocity of the body

• t is time taken

=> F = 16(14 - 3)/22

=> F = 16(11)/22

=> F = 16/2

=> F = + 8 N

Thus, the net force experienced by the cart is +8 N [option.A]

Answer 2

Answer:-

$\odot$$\sf {8N}$

$\bigcirc$$\sf {16N}$

$\bigcirc$$\sf {32N}$

$\bigcirc$$\sf {There\:is\:no\:applied\:Force\:on\:the\:object.}$

Calculations:-

Given:-

Mass=m=16kg

initial velocity=u=3m/s

Final velocity=v=14m/s

time=t=22seconds

To find:-

Force=F

Solution:-

• According to Newton 's second law of motion

${\boxed{\sf {F={\dfrac {m (v-u)}{t}}}}}$

• Substitute the values

${:}\longmapsto$$\sf {F={\dfrac {16 (14-3)}{22}}}$

${:}\longmapsto$$\sf{F={\dfrac {16×{\cancel {11}}}{{\cancel{22}}}}}$

${:}\longmapsto$$\sf {F={\dfrac {16}{2}}}$

${:}\longmapsto$${\underline{\boxed{\bf {Force=8N}}}}$

$\therefore$$\sf {Net\;force\;experienced \;by} \\ \sf {the\;cart\;is{\quad}8N.}$