Math, asked by NoBrainz, 1 year ago

plz help...literally no one is helping. give ans in pic plz

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Answers

Answered by siddhartharao77
1

(14).

Given Equation is x^2 + bx + c = (x + p)(x - q)

= > x^2 + bx + c = x^2 - xq + px - pq

= > x^2 + bx + c = x^2 - (p - q)x - pq.

Here,

the value of b = p - q, c = -pq.

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Now,

= > x^2 - bxy + cy^2

= > x^2 - (p - q)xy - pqy^2

= > x^2 - pxy + qxy - pqy^2

= > x(x - py) + qy(x - py)

= > (x + qy)(x - py).

Hope this helps!


NoBrainz: cause sometimes i dont get answers at all
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NoBrainz: some people force me
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