Math, asked by dkkddk, 5 months ago

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Answered by BrainlyEmpire
67

Given:-

A Function-

\bf{sec(tan(x^{4}+4))}

To Find:-

Differentiation of given function w.r.t. to x

Solution:

We know that,

\leadsto\bf{\dfrac{d}{dx}(sec\:x)=sec\:x\:tan\:x}

\leadsto\bf{\dfrac{d}{dx}(tan\:x)=sec^{2}x}

\leadsto\bf{\dfrac{d}{dx}(x^{n})=nx^{n-1}}

\leadsto\bf{\dfrac{d}{dx}(constant)=0}

Now,

On differentiating given function w.r.t. x, we get

\sf{\dfrac{d}{dx}(sec(tan(x^{4}+4)))}

\sf{sec(tan(x^{4}+4))tan(tan(x^{4}+4))\dfrac{d}{dx}(tan(x^{4}+4))}

\sf{sec(tan(x^{4}+4))tan(tan(x^{4}+4))sec^{2}(x^{4}+4)\dfrac{d}{dx}(x^{4}+4)}

\sf{sec(tan(x^{4}+4))tan(tan(x^{4}+4))sec^{2}(x^{4}+4)(4x^{3}+0)}

\sf\pink{sec(tan(x^{4}+4))tan(tan(x^{4}+4))sec^{2}(x^{4}+4).4x^{3}}

Answered by sainiinswag
1

Answer:

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