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Take the integral:
∫sin²(x) dx
Write sin²(x) as 1/2 - 1/2 cos(2 x):
= ∫(1/2 - 1/2 cos(2 x)) dx
Integrate the sum term by term and factor out constants:
= -1/2 ∫cos(2 x) dx + 1/2 ∫1 dx
For the integrand cos(2 x), substitute u = 2 x and du = 2 dx:
= -1/4 ∫cos(u) du + 1/2 ∫1 dx
The integral of cos(u) is sin(u):
= -sin(u)/4 + 1/2 ∫1 dx
The integral of 1 is x:
= x/2 - sin(u)/4 + constant
Substitute back for u = 2 x:
= x/2 - 1/4 sin(2 x) + constant
Which is equal to:
Answer:
= 1/2 (x - sin(x) cos(x)) + constant
∫sin²(x) dx
Write sin²(x) as 1/2 - 1/2 cos(2 x):
= ∫(1/2 - 1/2 cos(2 x)) dx
Integrate the sum term by term and factor out constants:
= -1/2 ∫cos(2 x) dx + 1/2 ∫1 dx
For the integrand cos(2 x), substitute u = 2 x and du = 2 dx:
= -1/4 ∫cos(u) du + 1/2 ∫1 dx
The integral of cos(u) is sin(u):
= -sin(u)/4 + 1/2 ∫1 dx
The integral of 1 is x:
= x/2 - sin(u)/4 + constant
Substitute back for u = 2 x:
= x/2 - 1/4 sin(2 x) + constant
Which is equal to:
Answer:
= 1/2 (x - sin(x) cos(x)) + constant
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this is the answer.......
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