Math, asked by zainazodiac, 10 months ago

plz help me and create the simultaneous equations for this question
Q=1 In five years time Kate,s father will be three times as old as Kate.Four years ago, her father was six times as old as her.Find their present ages. answer this plz ill mark u as brainliest and give u 50 points

Answers

Answered by sushanimje
2

Let

Present age of father = f

Present age of son = s

In five years time,

Man age = f+5

Son age = s+5

then father will be three times as old as his son.

f+5=3(s+5)

f+5=3s+15

f=3s+15-5

f=3s+10..........(1)

Four years ago

Man age = f-4

Son age = s-4

then father was six times as old as his son.

 

f-4=6(s-4)

f-4=6s-24

f=6s-24+4

f=6s-20..........(2)

Put the value of f from (1) to (2)

3s+10=6s-20

3s-6s=-10-20

-3s=-30

-3s/-3=-30/-3

s=10

Put the value of s in (1)

f=3(10)+10

f=30+10

f=40

Present age of father = f = 40 years old

Present age of son = s = 10 years old

Answered by Anonymous
6

Answer

Father age = 40 year

Son age = 10 year

Mark as brainliest.....

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