Question

plz help me answer this​

Answer 1

$\huge\mathfrak{\fcolorbox{lime}{cyan}{Answer࿐}}$

$\huge\mathcal\pink{Given:}$

⟹ Area of square = 50 sq.cm

$\huge\mathrm\green{★\: Formula\: ★}$

⟹ Area of square = side ²

⟹ (Hypotenuse)² = (base)² + (height)²

$\huge\mathcal\orange{Find:}$

⟹ Lenght of diagonal

$\huge\mathbb\color{chartreuse} Explanation:$

by using formula for

| area of square .|

⇒ Area of square = side ²

⇒ 50 = side²

⇒ ${side}^{2} = 50$

⇒ $side = \sqrt{50}$

⇒ $side = \sqrt{2 × 25}$

⇒ $side = 5\sqrt{2}$

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now we have side = $5\sqrt{2}$

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now finding Lenght of digonal by applying.

| Pythagoras theorem . |

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(Hyp)² = (base)² + (height)²

(Hyp)² = $(5\sqrt{2})² + (5\sqrt{2})²$

(Hyp)² = (25 × 2) + (25 × 2)

(Hyp)² = 50 + 50

(Hyp)² = 100

Hyp = $\sqrt{100}$

Hyp = 10 cm

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$\mathcal\red{Lenght\: of \:diagonal\: = \:10 \:cm }$

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$\huge\mathfrak\color{olive}Option\: correct\:is\:'2'$

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Note:

Hypotenuse (Hyp) = diagonal

Base and height will be same because the figure is triangle .

$\huge\mathfrak\color{crimson}I\:hope\:it\:helps\:you.$