plz help me answer this question
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Answer:
Given:
PQ = QO = OT = TP = 25cm
Therefore, PQOT is a square.
In ∆PST,
MS = 10cm
PT = 25cm
In trapezium PRQO, PR || QO,
PR = 15cm
QO = 25cm
Altitude = 20cm
Solution:
Area of the figure
= Area of quadrilateral PQOT + Area of triangle PST + Area of trapezium PRQO
= PQ^2 + 1/2×PT×MS + 1/2×(PR + QO) × Altitude
= 25^2 + 1/2×10×25 + 1/2×(15 + 25)×20
= 625 + 125 + 400
= 1150 sq. cm
Therefore, the total area of the figure is 1150 sq. cm.
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