Math, asked by SouravBangera1, 1 year ago

Plz help me answer (with steps)

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Answers

Answered by nikitasingh79
2
put x=-2 in the polynomial
x^3-3x^2-4x+k
(-2)^3 -3(-2)^2 -4(-2)+k
-8-12+8+k=0
-20+8+k=0
-12+k=0
K= 12

SouravBangera1: Thanks
Answered by wvaish
2
Hello friend

Let p(x)=x³-3x²-4x+k

It is given that (x+2) divides the polynomial p(x)

So x+2 is a factor of p(x)

So when p(x) is divided by x+2 it yields a remainder 0

By remainder theorem

y+2=0
x=-2

So p(-2)=0

p(-2)=-2³-3(-2)²-4(-2)+k

0= -8-12+8+k

0= -12+k

k=12

Hope it helps!

SouravBangera1: thanks
nikitasingh79: given is = (x+2) not (y+2)
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