Math, asked by NoBrainz, 1 year ago

plz help me anyone plz . I'm desperate coz nobody answers me. plz help. give answer in photo

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Answered by darky1

$put \: x = y = z = 1 \\ {(1 + x + \frac{1}{y} )}^{ - 1} + {(1 + y + \frac{1}{z} )}^{ - 1} + {(1 + z + \frac{1}{x} )}^{ - 1} = 1 \\ {(1 + 1 + 1)}^{ - 1} + {(1 + 1 + 1)}^{ - 1} + {(1 + 1 + 1)}^{ - 1} = 1 \\ {3}^{ - 1} + {3}^{ - 1} + {3}^{ - 1} - = 1 \\we \: take \: inverse \: in \: case \: of \: negative \: power \\ \frac{1}{3} + \frac{1}{3} + \frac{1}{3} = 1 \\ \frac{3}{3} = 1 \\ 1 = 1 \\ please \: mark \: as \: brainliest$

NoBrainz: i got it sir

NoBrainz: now i got it

darky1: still have doubt you can ask i m always there

NoBrainz: thanks sir a lot

NoBrainz: actually ur answer first came distorted

NoBrainz: i cant thank u enough sir

darky1: i m here to help you

darky1: mark as brainliest if you get that

NoBrainz: yeah but nobody else has given ans

darky1: alright

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