Question

plz help me Bhai 2 Ka dena sabse pahle​

Answer 1

Answer:

it's d

from class 9 NCERT ch 2 polynomial

Answer 2

Answer:

ii part

Step-by-step explanation:

factor (x+1)

x=-1

Now, put in the polynomials....

x^3+x^2+x+1

= -1+1-1+1

=0

For a no. let's assume 'X'

therefore for x to be a factor of a polynomial,

p(x) must be equal to 0....

therefore,

as we checked we only got ii part as 0 by putting -1 in place of x

Hence, ii is the answer...

Thanks mate,

I tried my best and hope this help :)