Plz help me by solving above question
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see . for equal roots b^2 - 4ac = 0
thus [-(k-2)] ^2 - 4×2×1 = 0
thus (k-2)^2 -8 = 0
k^2 -4k+ 4 -8 =0
k^2 -4k-4=0
which is again a quad. eqn.
thus roots will be
k = [-(-4)+- sq.root of (16-16)]/2×1. (using quad. formula)
thus k= (4+-0)/2 = 2...
hope it helps you.
thus [-(k-2)] ^2 - 4×2×1 = 0
thus (k-2)^2 -8 = 0
k^2 -4k+ 4 -8 =0
k^2 -4k-4=0
which is again a quad. eqn.
thus roots will be
k = [-(-4)+- sq.root of (16-16)]/2×1. (using quad. formula)
thus k= (4+-0)/2 = 2...
hope it helps you.
krit02:
I am sorry but your ans is wrong
u need not be. what's the answer then
Bro its 2(1+√2)
yeah . my answer is wrong . sorry sorry
How plZ can u explain me
Bro
Plz explain fast as possible
yes. by putting in the value of k in the given eqn
it doesn't give out equal roots . while the value you told me gives equal roots
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