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Given that ;
Diagonals of a Rhombus
In the Ratio = 3 : 4
Longer Diagonal = 12cm
Let
The Other Diagonal be x
3 : 4 = x : 12
3 / 4 = x / 12
Cross Multiplication :
3 × 12 = 4 × x
36 = 4x
x = 36 / 4
x = 9cm
Checking ;
Ratio :
9 : 12
3 : 4
Area of the Rhombus = 1 / 2 × Diagonal 1 × Diagonal 2
A = 1 / 2 d1 d2
A = 1 / 2 × 9 × 12
A = 9 × 6
A = 54
Hence ;
Area of the Rhombus ( A ) = 54cm²
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