Question

plz help me by solving this question...

I will mark correct answer as brainliest...​

Answer 1

Add 48 to both sides of the equation.

(x − 10)2 = 48

Take the square root of both sides of the equation to eliminate the exponent on the left side

x − 10 = ±√48

Simplify ±√48.

x−10=±4√3

x=4√3+10,−4√3+10

x=4√3+10,−4√3+10

Rlly hope this helps :)

Answer 2

Answer:

${\boxed{x = 10 + 4\sqrt{3}\; ,\; 10 - 4\sqrt{3}}}$

Step-by-step explanation:

(x - 10)² - 48 = 0

⇒ x² + 100 - 20x - 48 = 0 [Using (a - b)² = a² + b² - 2ab]

⇒ x² - 20x + 52 = 0

Now we need to use Quadratic Equation Formula.

$x = \dfrac{-b \pm\sqrt{b^2 - 4ac}}{2a}$

Now let's find $\sqrt{b^2 - 4ac}$ firstly.

$\sqrt{b^2 - 4ac}$

$= \sqrt{(-20)^2 - (4*1*52)}$

$= \sqrt{400 - 208}$

$= \sqrt{192} \\ = 8\sqrt{3}$

Now, $\alpha = \dfrac{-b + \sqrt{b^2 - 4ac}}{2a}$

$= \dfrac{-(-20) + 8\sqrt{3}}{2*1}$

$= \dfrac{20 + 8\sqrt{3}}{2}$

$= \dfrac{\not2(10 + 4\sqrt{3})}{\not2}$

$= 10 + 4\sqrt{3}$

Now, $\beta = \dfrac{-b - \sqrt{b^2 - 4ac}}{2a}$

$= \dfrac{-(-20) - 8\sqrt{3}}{2*1}$

$= \dfrac{20 - 8\sqrt{3}}{2}$

$= \dfrac{\not2(10 - 4\sqrt{3})}{\not2}$

$= 10 - 4\sqrt{3}$

$\therefore{\boxed{\alpha = 10 + 4\sqrt{3}}}$

$\therefore{\boxed{\beta = 10 - 4\sqrt{3}}}$

$\therefore{\boxed{x = 10 + 4\sqrt{3}\; ,\; 10 - 4\sqrt{3}}}$