Math, asked by ItzRiya07, 1 month ago

plz help me.. don't spam. thanks for the help.​

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Answers

Answered by Anonymous
26

\huge\colorbox{lightgreen}{☑Verified Answer}

∆AOC = x°

First draw line passing with O

And then , now

∆OAB = 104°

the by (consecutive)

180 = ∆OAB + ∆1

∆1 = (180-104)

∆1 = 76°

Now Second Step,

∆OCD = 116°

Then, 180 = ∆OCD + ∆2

∆2 = (180-116)

∆2 = 64°

= Now add ∆1 + ∆2

= (76+64) °

x° = 140°

Answered by sahvaishnavi7
48

\huge\mathrm\blue{Answer}

∆AOC = x°

First draw line passing with O

And then , now

∆OAB = 104°

the by (consecutive)

180 = ∆OAB + ∆1

∆1 = (180-104)

∆1 = 76°

Now Second Step,

∆OCD = 116°

Then, 180 = ∆OCD + ∆2

∆2 = (180-116)

∆2 = 64°

= Now add ∆1 + ∆2

= (76+64) °

x° = 140°

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