Question

plz help me fast !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!​

Answer 1

Answer:

$x {}^{2} + \frac{1}{ {x}^{2} } = 18 \\ x - \frac{1}{x} = ? \\ (x - \frac{1}{x} ) {}^{2} = {x}^{2} + \frac{1}{ {x}^{2} } - 2 \\ (x - \frac{1}{x} ) {}^{2} = 18 - 2 \\ (x - \frac{1}{x} ) {}^{2} = 16 \\ x - \frac{1}{x} = \sqrt{16} \\ x - \frac{1}{x} = 4$

Answer 2

Answer:

hope it will be helpful

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