Question

plz help me fast


find the zeros of polynomial X square + 2 X + 1 = 0​

Answer 1

Answer:

Zeros of polynomial = -1 , -1

Step-by-step explanation:

$x^{2} +2x+1=0\\(x+1)^2 = 0\\(x+1)(x+1) = 0\\x = -1,-1$

Answer 2

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• QuestioN :

$\mapsto \sf \: {x }^{2} + 2x + 1 = 0$

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Process - 1

$\sf \: {x}^{2} + 2x + 1 = 0$

$\implies \: \sf {x}^{2} + x + x + 1 = 0$

$\implies \sf \:x(x + 1) + 1(x + 1) = 0$

$\implies \sf \: {(x + 1)}^{2} = 0$

$\implies { \underline{ \boxed{\sf \: x = - 1}}}$

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Process - 2

$\sf \: {x}^{2} + 2x + 1 = 0$

$\implies \sf \: {(x + 1)}^{2} = 0 \: \: \: [ a²+b²+2ab=(a+b)² ]$

$\implies { \underline{ \boxed{\sf \: x = - 1}}}$

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Process - 3

$\sf \: {x}^{2} + 2x + 1 = 0$

$\mapsto \boxed{ \sf \: x \: = \frac{ - b ±\sqrt{ {b}^{2} - 4ac } }{2a}} \: \: \: \: \: \: \: \: \bf [ \: Formula \: ]$

$\implies \sf \: x \: = \frac{ - 2 ±\sqrt{ \cancel{{2}^{2}} - \cancel{4} } }{2}$

$\implies { \underline{ \boxed{\sf \: x = - 1}}}$

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HOPE THIS IS HELPFUL...