Math, asked by lucy2019, 10 months ago

plz help me fast plz ​

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Answered by Anonymous
1

Step-by-step explanation:

2sinAcosA/(1-1+2sin²A).(1-cosA)/cosA

cosA/sinA.(1-cosA)/cosA

(1-cosA)/sinA

{1-(1-tan²A/2)/(1+tan²A/2)}/{2tanA/2/1+tan²A/2}

(2tan²A/2)/(1+tan²A/2)/{2tanA/2/1+tan²A/2}

tanA/2

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