Math, asked by ash55320, 10 months ago

plz help me fastttttt it's very very urgent

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ash1776: whats ur real name
ash55320: yours
abhay1tomar: bhai sun
abhay1tomar: d=0 hai
ash55320: haji
abhay1tomar: b sq. -4ac=0 ye rakh answer ayega
abhay1tomar: p= 2 & p= -6
ash55320: p=-2,p=6
abhay1tomar: yes ye hi answer hai
ash55320: yes

Answers

Answered by Anonymous
1

Answer:


Step-by-step explanation:

let the root be α

sum of roots α+α = -(p-2/4)

α=2-p/8

product of roots α² = 1/4

α=±1/2

putting α= 1/2 , p= -2

            α = -1/2 , p= 6

next part

sum of roots β+β= -(p-3)/1

β= 3-p/2

product of roots β² = p

β= ±√p

±√p= 3-p/2

squaring both sides

p = (3-p)²/4

4p= 9 + p² - 6p

p²-10p+9=0

p= 9,1


abhay1tomar: ok
ash55320: kkk
ash55320: all sum not understanding
ash55320: or getting
ash55320: kkkk
abhay1tomar: in 1 question d =0 & b2-4ac =0
abhay1tomar: after solve this equation p2-4p-12=0
ash55320: kkk
Answered by abhay1tomar
1

This is your 1st answer and 2nd answer do your self by this concept.

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