Plz help me guys........
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Answered by
42
Answer:
Now,
The initial Kinetic energy of the car ,
Similarly, final Kinetic energy of the car,
EK1 = 1/2 mv²
= 1/2 × 1500 × (50/3)²
= 1/2 × 1500 × 50/3 × 50/3
= 250 × 2500 ÷ 3
= 625000 / 3 J
Thus, the work done = change in Kinetic energy.
Answered by
237
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