Question

plz help me guys as fast as possible !​

Answer 1

Given :-

$\bigg(\dfrac{5}{9}\bigg)^{-2}\times\bigg(\dfrac{3}{5}\bigg)^{-3}\times \bigg(\dfrac{3}{5}\bigg)^0$

To Find :-

Evaluate

Solution :-

We know the rules of exponents

$\sf a^0=1$

$\sf\bigg(\dfrac{a}{b}\bigg)^{-m} = \bigg(\dfrac{b}{a}\bigg)^m$

$\sf \bigg(\dfrac{5}{9}\bigg)^{-2}\times\bigg(\dfrac{3}{5}\bigg)^{-3}\times 1$

$\sf\bigg(\dfrac{9}{5}\bigg)^2 \times\bigg(\dfrac{5}{3}\bigg)^3\times 1$

$\sf \dfrac{81}{25}\times \dfrac{125}{27}$

$\sf 3 \times 5$

$\sf 15$

Answer 2

the answer is

15i please mark me as brainliest iam growing