Question

plz help me guys plz plz plz​

Answer 1

V1 = 60km/hr D1 = 30 km

         T1 = ?

         V2 = 40 km /hr D2 = 30 km

         T2 = ?

Total Time = T1 + T2

We know that ,

           velocity = Distance /Time

Therefore ,

             V1 = D1/T1 or T1 = D1 / V1  => T1 = 30 km / 60 km /hr = 1/2 hr

              V2 = D2/T2 or T2 = D2/ V2  => T2 = 30 km / 40 km /hr = 3/4 hr

     Hence ,

               Total Time = T1 + T2 = 1/2 + 3/4 = 5/4 hrs

     we know that ,

               Average Velocity = Total Distance / total time taken = 30 + 30 / 5/4

                                         = 60/5/4 = 48 km /hr

Hence Average Velocity is 48km/hr and total time of journey = 5/4 hours.

My Short cut Method :-

           When a body travels equal distance with different velocities V1 and V2 , then Average Velocity is Calculated as

             Average Velocity = 2*V1*V2 / (V1 + V2 )

             here , V1 = 60 km/hr and V2 = 40 km/hr

     therefore ,

       Average Velocity = 2*60*40 / (60+40 )= 4800/100 = 48km/hr

Also we know that ,

           Average Velocity =  Total Distance / Total Time Taken

                     48 = 60 / Total Time Taken

                     or Total Time Taken = 60/48 = 5/4 Hrs .

♥️Thank u......!!♥️

Mark mee brainliest plz.....!!✌️✌️

Answer 2

Answer:

i) s= distance

S1= 30km v1 = 60km/hr

speed = distance/time, time= distance/ speed.

= 30/60= 1/2 hr or 30 mins.

S2= 30km,v2= 40km/hr.

= 30/40= 3/4 hr or 45 mins.

total time= 30+45= 75 mins or 1hr 15 mins.

Step-by-step explanation:

ii) average speed in this case is = (2v1v2)/v1+v2

v1= 60km/hr. v2= 40 km/hr.

(2*60*40)/60+40

= 4800/100= 48 km/hr.

please mark it as brainliest ❤️❤️ and follow me..