Question

plz help me I am not able to​

Answer 1

Answer:

It is given that,

tan(A+B)=tanA+tanB/1-tanA.tanB

tan(A)=1/2

tanB=1/3

tan(A+B)=1/2+1/3/1-1/2.1.3

tan(A+B)=5/6/1-1/6

tan(A+B)=5/6/5/6

tan (A+B)=1

Tan (A+B)=Tanπ/4

A+B=45°

Step-by-step explanation:

Hope it helps you.......

Answer 2

Given:-

tanA = $\frac{1}{2}$

tanB = $\frac{1}{3}$

tan(A+B)

= $\frac{tanA + tanB}{1-tanA.tanB}$

= $\frac{1/2+1/3}{1- 1/2*1/3}$

= $\frac{5/6}{5/6}$

= 1

= tan45°

tan(A+B) = tan45°

So, (A+B) = 45°