Question

plz help me I need it very fast plz

Answer 1

ANSWER;
we know that rhombus have all sides equal
in traingle adb,ad=ab
that means angle abd=angle adb
bad+abd+adb=180
2abd+bad=180
2abd=180-130
abd=50/2
abd=25

that means adb=25
 similarly angle cdb=angle cbd
 
a+b+c+d=360
130+25+x+25+x+130=360
310+2x=360
2x=50
x=25

Answer 2

As we know that in a rhombus,
1. Opposite angles have equal measure
2. Its diagonal bisects opposite angle
3. And the two diagonal of rhombus are perpendicular to each other.
By keeping these three points in our mind we can solve it like that
Now, draw diagonal AC and suppose that it bisects another diagonal BD at point 'O'.
Now, we have triangleBOC
In triangleBOC
AngleBOC=90°(a/c to 3rd property)
AngleOCB=65°(a/c to 2nd property)
Now, we can easily find the value of x=?
Now, in triangle BOC
angleBOC+angleOCB+angleCBO will be =180°
So, 90+65+x=180°
X=180°-155°
X=25°
Hence, value of x will be 25...