Question

PLZ HELP ME I want ans ​

Answer 1

Answer:

130 degree

Step-by-step explanation:

Draw a line FG passing through point C and parallel to line AB line FG || ray BA …….(i) [Construction] Ray BA || ray DE ….(ii) [Given] line FG || ray BA || ray DE …(iii) [From (i) and (ii)] line FG||rayDE [From (iii)] and seg DC is their transvensal ∴ ∠ DCF = ∠ EDC [Alternate angles] ∴ ∠ DCF = 100° [∵ ∠D = 100°] Now, ∠ DCF = ∠ BCF + ∠ BCD [Angle addition property] ∴ 100° = ∠BCF + 50° ∴ 100° – 50° = ∠BCF ∴ ∠BCF = 50° ….(iv) Now, line FG || ray BA and seg BC is their transversal. ∴ ∠ABC + ∠BCF = 180° [Interior angles] ∴ ∠ABC + 50° = 180° [From (iv)] ∴ ∠ABC = 180°- 50° ∴ ∠ABC = 130•

Answer 2

Answer:

130°

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