Question

plz help me

I will give mark as brainlest
the one who will do this​

Answer 1

Step-by-step explanation:

Given :-

AQ and AP are the two rays formed an angle PAQ

l is the bisector of angle A .B is the point on l .

BQ and BP are the perpendiculars from B to angle A .

To find :-

Show that following :

i) ∆ APB = ∆ APQ

ii) BP = BQ

Solution :-

From the given figure :

AQ and AP are the two rays formed an angle PAQ

l is the bisector of angle A

B is the point on l

BQ and BP are the perpendiculars from B to angle A

∆ APB and ∆ AQB are the two right angled triangles

From ∆APB and ∆AQB

<APB = <AQB = 90° ------(1)

< PAB = <QAB --------------(2)

AB = AB common side----(3)

From the above

∆ APB = ∆ AQB

By Angle - Angle - Side property.

∆ APB and ∆ AQB are congruent triangles

BP = BQ

Since Corresponding parts in the congruent triangles are equal.

Hence, Proved.

Used formulae:-

→ In two triangles, The two angles and the side are equal to the corresponding angles and side in other triangle then they are congruent.

→ Corresponding parts in the congruent triangles are equal.