Question

plz help me.

I will make as brain list answer
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Answer 1

roots = x and b

sum of roots= (x+b)

products of roots= (xb)

equation= 4x^2+2x-1=0

=x^2+(1/2)x -(1/4)=0

rule'

x^2 - sum of roots + product of root = 0

(x+b)= -(1/2)

(xb)= -(1/4)

$\frac{1}{x} +\frac{1}{b}$  =

=(x+b)/xb

=(-1/2)/(-1/4)

=2

Answer 2

Answer:

$let \: x \: and \: \beta \: are \: roots \: of \: given \: eqn. \\4 {x}^{2} +2 x - 1 = 0$

$sum \: of \: roots = x + \beta = \frac{ - b}{a} \\ product \: of \: roots = x \beta = \frac{c}{a}$

$we \: get \\ x \beta = \frac{ - 1}{4} \\ x + \beta = \frac{ - 1}{2}$

$\frac{1}{x} + \frac{1}{ \beta } = \frac{ \beta + x}{x \beta }$

$\frac{1}{x} + \frac{1}{ \beta } = \frac{ \frac{ - 1}{2} }{ \frac{ - 1}{4} }$

$\frac{1}{x} + \frac{1}{ \beta } = 2 \\ which \: is \: required \: result.$