Question

Plz help me if u gave some silly answers it will be reported

Answer 1

Answer:

b) we know that

a^3 - b^3 = (a - b)(a^2 + ab + b^2).............(1)

we can replace a and b by b and c or c and a or any other letters.

now, the first term is

(x^a/x^b)^(a^2+ab+b^2

= (x^(a-b))^(a^2+ab+b^2(

because a^m ÷ a^n = a^(m-n)

= x^(a-b)*(a^2+ab+b^2)

because (a^m)^n = a^(mn)

= x^(a^3 - b^3) (as discussed earlier at (1))

similarly, the second term will be

x^(b^3 - c^3)

and the third term will be

x^(c^3 - a^3)

on multiplying the terms we have

x^(a3 - b3 + b3 - c3 + c3 - a3)

= x^0

= 1. (because a^0 = 1, a not equal to zero)

c)

(64/125)^(-2/3) + 4^0*9^(5/2)*3^(-4) - √25/3√64 (1/3)^(-1)

(4/5)^(3*-2/3) + 1*3^(2*5/2)*(1/3)^4 - (5/4)*3

= (4/5)^-2 + 3^5 /3^4 - 15/4

= (5/4)^2 + 3^(5-4) - 15/4

= 25/16 + 3 - ,15/4

= (25+48-60)/16

= 13/16