Math, asked by Bajwa302, 1 year ago

Plz help me in 3 ques

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Answered by adarshparuthiyil
1

Answer:a =11 & b=6.


Step-by-step explanation:

Hi the steps are given below



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Answered by siddhartharao77
1

Answer:

a = 11, b = -6

Step-by-step explanation:

(iii)

Given:\frac{5 + 2\sqrt{3}}{7+4\sqrt{3}} = a + b\sqrt{3}

On rationalizing, we get

=>\frac{5+2\sqrt{3}}{7+4\sqrt{3}}*\frac{7-4\sqrt{3}}{7-4\sqrt{3}}

=>\frac{(5+2\sqrt{3})(7-4\sqrt{3})}{(7+4\sqrt{3})(7-4\sqrt{3})}

=>\frac{35-20\sqrt{3}+14\sqrt{3}-24}{(7)^2-(4\sqrt{3})^2}

=>\frac{11-6\sqrt{3}}{49-48}

=>11 - 6\sqrt{3}

Now,

⇒ 11 - 6√3 = a + b√3

⇒ 11 + (-6)√3 = a + b√3

On comparing, we get

a = 11, b = -6


Hope it helps!

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