Question

plz help me in question no 2 and 4

Answer 1

Q 2

Since LN = LM
So, angle LNM = angle LMN
20° = angle LMN

Now angle sum property
angle L + angle M + angle N = 180°
b + 20 + 20 = 180
b + 40 = 180
b = 180 - 40
b = 140°

Q 4

In triangle PQR
PR = QR
angle RPQ = angle RQP
59° = angle RQP

Now by angle sum property in triangle PQR
angle PRQ + angle PQR + angle QPR = 180°
x + 59 + 59 = 180
x + 118 = 180
x = 180 - 118
x = 62°

angle PRQ + angle PRS = 180°(linear pair angle)
62 + angle PRS = 180
angle PRS = 180 - 62
angle PRS = 118°

Now by angle sum property in triangle PRS
angle PSR + angle SRP + angle RPS = 180°
y + 118 + 32 = 180°
y + 150 = 180°
y = 180 - 150
y = 30°

Hope it helps!!!!!!!