Question

plz help me in question no 2 and 4

Answer 1

(ii) ar sq. ABCD = Side x Side = 47 cm^2

= Side^2 = 47 cm^2

= Side = √47 = AB = BC = AD = CD

ar sq. GDEF,

= side^2 = 34 cm^2

= side = √34 = GD = DE = EF = GF

In ∆ ADG,.

AD^2 + GD^2 = AG ^2 ( Pythagoras theorem)

AD = √47, GD = √34

= (√47)^2 + (√34)^2 = AG^2

= 47 + 34 = AG^2

= 81 = AG^2

AG = 9 cm

Area sq. AGHI ,

Side x Side = AG x AG = 9 x 9 = 81 cm^2


(iv) ar square ABCD

= Side^2 = 1369

= Side = 37 cm = DC

Similarly,

Ar sq. ECGF

= 144 = Side^2

= Side = 12 cm = EC

In ∆ DEC,

EC^2 + DE^2 = DC^2

(12)^2 + DE^2 = (37)^2

DE^2 = 1369 - 144

DE^2 = 1225

DE = 35 cm

Area sq IDEH,

Side^2 = DE^2 = 1225 cm^2