plz help me in this fast
solve for x:√3x^2+11x+6√3=0
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hii here is ur answer
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siddhartharao77:
Its not x/root 3x^2. Its root3x^2 only.
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√3 x² + 11x + 6√3 = 0
x ( √3x + 2) + 3√3 ( √3x + 2) = 0
(x + 3√3) ( √3x + 2) = 0
x = - 3√3 or -2/√3
Hope it will be helpful...
x ( √3x + 2) + 3√3 ( √3x + 2) = 0
(x + 3√3) ( √3x + 2) = 0
x = - 3√3 or -2/√3
Hope it will be helpful...
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